[Retros] 6-fold pin
christoph at fieberg.com
Sun Nov 12 17:30:38 EST 2006
8/2B3B1/3n1n2/2RbkbR1/3rpr2/2B1K1B1/8/7Q w - - 0 1
This to achieve in a SPG would be a real challenge.
>Date: Sun, 12 Nov 2006 08:23:24 +0100 (CET)
>From: Nicolas.Dupont at math.univ-lille1.fr
>To: afretro at yandex.ru, "The Retrograde Analysis Mailing List"
><retros at janko.at>
>Andrey asked :
> > How many pins can be effective in the mate position of an SPG (regardless
> > of the mating piece)? Three? Four? Or even more?
>It's not so complicated to get four...
>1.Pa2-a4 Ph7-h5 2.Pa4-a5 Ph5-h4 3.Pa5-a6 Ph4-h3
>4.Pa6xb7 Ph3xg2 5.Ph2-h4 Pa7-a5 6.Ph4-h5 Pa5-a4
>7.Ph5-h6 Pa4-a3 8.Ph6-h7 Pa3-a2 9.Th1-h6 Pa2xb1=T
>10.Cg1-h3 Pg2-g1=T 11.Ta1-a3 Tg1-g5 12.Ta3-g3 Ta8-a1
>13.Ph7xg8=T Cb8-a6 14.Pb7-b8=T Fc8-b7 15.Tb8-c8 Fb7-h1
>16.Pe2-e4 Pc7-c5 17.Ff1-b5 Pc5-c4 18.Dd1-h5 Tg5-c5
>19.Pf2-f3 Pe7-e5 20.Th6-e6
>Obtaining five effective pins needs of course a completely different kind
>of strategy (the thematic king must probably stand around the center of
>the board). It should probably exists, although I have strictly no idea of
>how getting it.
>Other researches can be made on that 4-pins task. For examples :
>- fewer moves
>- no visible promoted piece
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