[W126 Coupe] optimum air to fuel ratio

Shayegan, Richard rishayegan at davidson.edu
Thu Aug 25 08:43:27 EDT 2005


Ok, well I got the archives to work and saw that it was said 13.5:1 more
power than 14.7:1. Why is this so? As far as I always knew, leaner =
more power but also more heat. I know that's the case with 2-stroke R/C
cars, and it seems like the same logic should follow toward 4-stroke
(more oxygen makes a bigger explosion). On one of the sites that was
given as evidence as to 13.5:1 being better, it also said to get more
power run leaner and a higher octane...so how can 13.5 give more power
than 14.7?
Thanks,
Richard

-----Original Message-----
From: mbcoupes-bounces at mbcoupes.com
[mailto:mbcoupes-bounces at mbcoupes.com] On Behalf Of Shayegan, Richard
Sent: Wednesday, August 24, 2005 11:43 PM
To: Mercedes Coupes Mailing Lists
Subject: [W126 Coupe] optimum air to fuel ratio

I remember reading on here that the optimum air to fuel ratio for fuel
efficiency is not the same as for power. But I forget does the more
powerful mixture have more air or more fuel?
Thanks,
Richard
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